Array Practice (Solutions)

By: Jerrett Longworth, Idel Martinez

Fill in the blanks for the program to create an array of odd numbers from 1 to max, which will be inputted by the user.

Answer:

int main(void)
{
  int max;
  printf("Enter the maximum number to go to: ");
  scanf("%d", &max);

  int size = (max + 1) / 2;
  int odd = 1;
  int odd_numbers[size];

  for (int i = 0; i < size; i++)
  {
    odd_numbers[i] = odd;
    odd = odd + 2;
  }

  for (int i = 0; i < size; i++)
  {
    printf("%d\n", odd_numbers[i]);
  }

  return 0;
}

Fill in the blanks for the program to initialize the final array with the squares of the numbers of the initial array. That is, if initial is array of with elements [1, 2, 3, 4, 5], our program will initialize the corresponding final array with the values squared as [1, 4, 9, 16, 25]. Make sure you accept arrays of any size!

Answer:

double square(double num)
{
  return num * num;
}

void init_square_array(double *initial, double *final, int count)
{
  for (int i = 0; i < count; i++)
  {
    final[i] = square(initial[i]);
  }
}

void print_array(double *array, int count)
{
  printf("These are the values of the array!\n");
  for (int i = 0; i < count; i++)
  {
    printf("%lf\n", array[i]);
  }
}

int main(void)
{
  double numbers[] = { 1, 2, 3, 4, 5 };
  double numbers_results[5];

  double evens[10];
  double evens_results[10];

  double x = 2;
  for (int i = 0; i < 10; i++)
  {
    evens[i] = x;
    x = x + 2;
  }

  init_square_array(numbers, numbers_results, 5);
  init_square_array(evens, evens_results, 10);

  print_array(numbers_results, 5);
  print_array(evens_results, 10);

  return 0;
}

Create a function that takes two integer arrays, array1 and array2, and the length of array1, that copies the contents of array1 into array2. Assume that array2 has at least as many elements as array1.

Answer:

void copy_array(int *array1, int *array2, int length)
{
  for (int i = 0; i < length; i++)
  {
    array2[i] = array1[i];
  }
}

What is wrong with the following code snippet? (Challenge yourself to avoid using your code editor.)

#include <stdio.h>

void print_float_array(float *array, int count)
{
  for (int i = 0; i < count; i++)
  {
    printf(" %f", array[i]);
  }
  printf("\n");
}

int main(void)
{
  float values[] = {3.14, 2.718, 6.9, 42.0};

  for (int i = 0; i < 4; i++)
  {
    print_float_array(values[i], 4);
  }

  return 0;
}

Answer: print_float_array() accepts a float array and a count, but line 18 is passing a float value, not an array. Also, since we iterate the for loop 4 times in main(), in which we call a function that goes throes another loop 4 times, we would be doing twice the amount of work. To fix it, we would simplify the code in main() to:

int main(void)
{
  float values[] = {3.14, 2.718, 6.9, 42.0};

  print_float_array(values, 4);

  return 0;
}